Chemistry
Diluting 6 mol per liter stock to 500 milliliters of 0.5 mol per liter solution takes 41.7 milliliters of stock. Enter any three of stock concentration, stock volume, target concentration and final volume, and the dilution solver fills in the fourth.
Fill in any three of the four boxes and leave the fourth empty. Concentrations in mol/L, volumes in milliliters.
| Stock concentration | |
| Stock volume | |
| Target concentration | |
| Final volume | |
| Dilution factor | |
| Solvent to add | |
| Solute amount | |
| Formulas used |
All calculations run in your browser, and nothing you type is uploaded or stored.
Solve any dilution: fill in three of stock concentration, stock volume, target concentration and final volume, and the solver fills in the fourth. The page covers moles, molarity and where the formula stops.
Key takeaways
- A mole counts 6.02214076 x 10^23 particles, an exact SI definition since 2019
- Molarity is moles per liter: 0.1 mol of sodium chloride in 500 mL makes a 0.2 mol/L solution
- The dilution equation C1 V1 = C2 V2 works because dilution moves moles around without adding or removing any
- The 6 mol/L to 500 mL example needs 41.7 mL of stock, a 12-fold dilution with 458.33 mL of water added
- The equation assumes volumes add, so add concentrated acid to water and never trust it for the acid into water case
On this page
- What this page covers, and which tool fits your task
- Moles: the counting unit that makes reactions predictable
- Molarity: concentration you can pipette against
- The dilution equation: C1 V1 = C2 V2
- Worked examples: buffers and serial dilutions
- Where C1 V1 = C2 V2 breaks down
- Safety basics the formulas will not tell you
What this page covers, and which tool fits your task
This page handles the calculation that comes up most often at the bench: you already own a stock solution at a known concentration and need a weaker working solution at a set volume. Enter any three of the four quantities and the solver at the top of the page produces the fourth, along with the dilution factor and the amount of solute involved.
Different starting points call for different tools. If you are weighing out a dry chemical to build a solution from scratch, the molarity calculator converts mass through moles into a target concentration. If you only need grams to moles, the grams-to-moles calculator does that single step. Household products such as bleach or rubbing alcohol are covered by the cleaning dilution pages, which work in volume ratios rather than moles. The table below sorts it out.
| Task | Right tool |
|---|---|
| Dilute a stock you already have to a target concentration | This page |
| Weigh a solid to make a solution of a set molarity | Molarity calculator |
| Convert a weighed mass into moles | Grams-to-moles calculator |
| Mix cleaning products by volume ratio | Cleaning dilution pages |
| Relate concentration to gas pressure and volume | Ideal gas law calculator |
Moles: the counting unit that makes reactions predictable
Chemists count atoms and molecules the way paper mills count sheets: in fixed bundles. One mole is exactly 6.02214076 x 10 to the 23 particles, a value fixed by international agreement when the SI was redefined in 2019, as recorded in the NIST SI units page. The bundle is chosen so that the mass of one mole in grams matches the molecular weight in daltons, which is what makes the unit useful for weighing.
Molar mass comes straight off the periodic table. Sodium chloride is one sodium (22.99 g/mol) plus one chlorine (35.45 g/mol), so 22.99 + 35.45 = 58.44 grams per mole. Weigh out 5.844 grams of table salt and you have 5.844 / 58.44 = 0.1 moles, or one tenth of Avogadro's number of formula units.
Glucose shows how the sum extends to bigger molecules: six carbons, twelve hydrogens and six oxygens contribute 72.066 + 12.096 + 95.994 = 180.156 grams per mole, usually rounded to 180.16. Every stoichiometry calculation on this page rests on that one conversion between a mass you can weigh and a count of particles.
Molarity: concentration you can pipette against
Molarity divides moles by liters of solution and gets the unit chemists abbreviate as M. Dissolve 0.1 moles of sodium chloride and bring the volume up to 500 milliliters (0.5 liters), and the concentration is 0.1 / 0.5 = 0.2 mol per liter, written 0.2 M. The final volume is the volume of the whole solution, solvent included, not the volume of water you added.
A laboratory shortcut saves unit juggling: moles per liter times milliliters equals millimoles. Pouring 41.7 mL of 6 mol per liter stock therefore transfers 6 x 41.7 = 250.2 mmol, about a quarter mole. The dilution solver reports this number so you can sanity-check two recipes against each other.
| Solute | Molar mass (g/mol) | Mass dissolved | Final volume | Concentration |
|---|---|---|---|---|
| Sodium chloride | 58.44 | 5.844 g | 500 mL | 0.2 mol/L |
| Glucose | 180.16 | 9.008 g | 250 mL | 0.2 mol/L |
| Sucrose | 342.3 | 34.23 g | 1,000 mL | 0.1 mol/L |
Check one row end to end: 9.008 / 180.16 = 0.05 moles of glucose, and 0.05 / 0.25 = 0.2 mol per liter in a final 250 mL. Same target as the salt row, entirely different chemistry.
The dilution equation: C1 V1 = C2 V2
Dilution adds solvent, never solute. The moles you started with are the moles you end with, so concentration times volume must match on both sides: C1 V1 = C2 V2. In moles per liter and milliliters, each side evaluates in millimoles, which keeps the arithmetic in comfortable ranges.
| Solve for | Rearranged formula |
|---|---|
| Final volume V2 | V2 = C1 x V1 / C2 |
| Target concentration C2 | C2 = C1 x V1 / V2 |
| Stock volume V1 | V1 = C2 x V2 / C1 |
| Stock concentration C1 | C1 = C2 x V2 / V1 |
The worked example from the top of the page: make 500 mL of 0.5 mol per liter solution from 6 mol per liter stock. The stock volume is V1 = 0.5 x 500 / 6 = 41.67 mL. Measure 41.67 mL of stock, add solvent to the 500 mL mark (500 - 41.67 = 458.33 mL of water), and mix. The dilution factor is 500 / 41.67 = 12.0, so this is a twelve-fold dilution.
When a recipe names the dilution instead, work the other way: a 1x working buffer from 10x stock is a ten-fold dilution, so one part stock takes nine parts water.
Worked examples: buffers and serial dilutions
Buffers show the equation at its most routine. To make 500 mL of 1x TAE electrophoresis buffer from 10x concentrate, use V1 = 1 x 500 / 10 = 50 mL of concentrate and dilute to volume: 50 + 450 = 500 mL total. The same one-to-nine split works for any 10x concentrate at any final volume.
Serial dilutions chain the single step. Transfer one part of 100 mg per mL stock into nine parts of solvent and you have 10 mg per mL; repeat into fresh solvent and each tube drops another factor of ten. After four transfers the concentration is 10 x 10 x 10 x 10 = 10,000 times weaker than the stock, which is 0.01 mg per mL. Serial dilutions are the standard route when a working range spans orders of magnitude, as in plate counts and ELISA standard curves.
| Tube | Dilution so far | Concentration (mg/mL) |
|---|---|---|
| Stock | 1 | 100 |
| Transfer 1 | 1:10 | 10 |
| Transfer 2 | 1:100 | 1 |
| Transfer 3 | 1:1,000 | 0.1 |
| Transfer 4 | 1:10,000 | 0.01 |
For the solver, run each tube as its own dilution step rather than entering a chain, and carry the computed concentration forward as the next step's stock.
Where C1 V1 = C2 V2 breaks down
The equation leans on one physical claim: volumes add. Most dilute aqueous work obeys that closely enough for any pipette to measure, but the edges of the map are worth knowing.
Alcohol and water contract. Mix 50 mL of ethanol with 50 mL of water and the total lands near 97 mL, not 100, because the molecules pack together. Proof spirits and lab reagents made with high ethanol fractions need volume-by-weight tables instead of a straight dilution factor.
Concentrated acids are not 100 percent solute. Commercial concentrated hydrochloric acid is about 37 percent HCl by weight with a density near 1.19 g per mL, so its molarity comes from a weight percent calculation, not from the bottle percentage alone. Use the supplier's stated molarity as C1 and the equation holds.
Highly concentrated stocks stack activity on top of concentration. At high ionic strength, effective concentration (activity) drifts from the analytical value printed on the bottle. Dilutions of several fold are fine; predicting the pH of a barely diluted concentrated acid is a different problem.
Finally, keep units consistent. Concentrations on both sides must be the same kind (both molar or both percent), and volumes on both sides the same unit. The solver assumes mol/L and mL and reports the moles balance so a unit slip shows up as a mismatch.
Safety basics the formulas will not tell you
Calculation is the easy half of making a solution. The other half is handling the chemicals, and the rules there come from practice, not algebra.
- Add acid to water, never water to acid. Concentrated acid releases enough heat on dilution to boil a splash of water back out of the vessel; adding the acid slowly to a larger water volume keeps that heat spread out.
- Wear splash goggles and gloves rated for the chemical, and work with volatile or irritating solvents in a fume hood.
- Label every prepared solution with contents, concentration, date and initials. An unlabeled 6 mol per liter acid is a hazard; the same bottle labeled is a reagent.
- Check the safety data sheet before first use of any chemical, and follow your institution's chemical hygiene plan.
Employers in the United States follow the OSHA laboratory safety guidance, which covers the labeling, training and documentation that keep a lab audit-ready. Home and school labs should hold themselves to the same standard in miniature: small quantities, eye protection, and dilution directions worked out before anything is poured.
Frequently asked questions
What is the dilution equation in words?
Concentration times volume before dilution equals concentration times volume after, because dilution adds solvent but no solute. In symbols, C1 V1 = C2 V2, with each side evaluating to the same number of moles.
How do I make 500 mL of 0.5 M solution from 6 M stock?
V1 = 0.5 x 500 / 6 = 41.67 mL. Measure 41.67 mL of the 6 M stock, add water to the 500 mL mark, and mix. That is a twelve-fold dilution, and you added 458.33 mL of water.
What is a mole in simple terms?
A bundle of 6.02214076 x 10 to the 23 particles, chosen so that one mole of a substance weighs its molecular weight in grams. One mole of sodium chloride weighs 58.44 grams, which is about a rounded spoonful of table salt.
How do I calculate molarity from grams?
Two steps: divide the mass by the molar mass to get moles, then divide by the volume in liters. For 5.844 g of salt in 500 mL, 5.844 / 58.44 = 0.1 mol, and 0.1 / 0.5 = 0.2 mol per liter. The molarity calculator on this site runs the whole chain from mass.
What is the difference between molarity and molality?
Molarity divides moles by liters of solution, so it changes slightly with temperature as the solution expands. Molality divides moles by kilograms of solvent, which is temperature independent, and it is the preferred unit for boiling point and freezing point work.
Why does C1 V1 = C2 V2 work?
Dilution only moves solvent, so the moles of solute are unchanged. Moles equal concentration times volume on both sides, and setting those two products equal gives the equation. The solver reports the millimole balance from both sides so you can see it hold.
What does a 1:10 dilution mean?
One part of the concentrated material plus nine parts of solvent, for a total of ten parts and a concentration one tenth of the original. In the solver, a 1:10 step is any combination where V2 is ten times V1, such as 10 mL of stock diluted to 100 mL.
How do serial dilutions multiply?
Each step multiplies the previous dilution. Four sequential 1:10 transfers give 10 x 10 x 10 x 10 = 10,000-fold total dilution, taking 100 mg per mL down to 0.01 mg per mL. Chain the steps one at a time in the solver, using each result as the next stock.
Can I use the calculator with percent solutions?
Yes, as long as both concentrations use the same basis and the volumes are in the same units. Going from 70 percent alcohol to 500 mL of 30 percent: V1 = 30 x 500 / 70 = 214.29 mL. Ethanol-water contraction means the final volume is approximate for high alcohol fractions.
How much water do I add in the 6 M example?
Add water to the final volume rather than by a separate number: 500 - 41.67 = 458.33 mL. In volumetric glassware you would measure the 41.67 mL of stock into a flask and fill to the 500 mL mark, which absorbs the small volume effects the arithmetic ignores.
Should I add acid to water or water to acid?
Always acid to water. Dilution releases heat, and a thin stream of acid into a volume of water sheds that heat safely, while water poured onto concentrated acid can flash to steam and spatter acid. The dilution equation is unchanged either way; the safety outcome is not.
What does a 10x buffer concentrate mean?
It is ten times the concentration of the 1x working solution. Dilute one part concentrate with nine parts water: 50 mL of 10x TAE plus 450 mL of water makes 500 mL of 1x. The solver reproduces this with C1 = 10, C2 = 1 and V2 = 500.
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