Lelifi·tools

Activation Energy Calculator

Two rate constants measured 20 K apart give an activation energy of 64.23 kJ/mol, or 0.666 electronvolts per molecule. Enter k1 = 2.0 x 10^-4 at 300 K and k2 = 1.0 x 10^-3 at 320 K and the page returns a pre-exponential factor of 3.05 x 10^7 s^-1 and a Q10 of 2.29, so the rate roughly doubles every 10 K.

Enter two rate constants with their temperatures, or a known Ea, and get activation energy in kJ/mol and eV, the pre-exponential factor A, and Q10.

By the Lelifi editors ·

Key takeaways

Energy profile of a reaction with Ea = 64.2 kJ/molReactantsProductstransition stateEa = 64.2 kJ/molthe reverse barrier is Ea plus the reaction enthalpyOnly collisions carrying at least Ea can cross the barrier, and raising T raises that fraction.
The activation energy is the climb from reactants to the transition state. At 64.2 kJ/mol a 10 K rise near room temperature multiplies the rate by about 2.3.
Arrhenius plot: ln k against 1/T1/Tln kslope = -Ea / Rintercept = ln AStraight points mean one mechanism; curvature or a break means A or the pathway changes with temperature.
On an Arrhenius plot the slope of ln k against 1/T equals -Ea / R, so a 64.2 kJ/mol barrier appears as a slope of about -7,725 K.
On this page
  1. The Arrhenius equation in one line
  2. The gas constant and the exact CODATA value
  3. Worked example 1: 64.2 kJ/mol from two rate constants
  4. Worked example 2: predicting a rate constant at a new temperature
  5. Reading an Arrhenius plot
  6. Ea values for common reaction families
  7. Eyring, Q10, and the eV convention
  8. Where the model stops

The Arrhenius equation in one line

The Arrhenius equation says that a rate constant k rises with temperature T as k = A x exp(-Ea / (R x T)). Ea is the activation energy in joules per mole, R is the molar gas constant, and A is the pre-exponential factor, also called the frequency factor, which collects collision frequency and orientation effects. The exponential term is the fraction of collisions that carry at least Ea of energy, so raising T raises that fraction and the rate climbs.

The form the calculator uses most is the two point relation. Take the equation at two temperatures, divide one by the other so A cancels, and take logs:

ln(k2 / k1) = (Ea / R) x (1/T1 - 1/T2)

Solve for Ea and you get Ea = R x ln(k2 / k1) / (1/T1 - 1/T2). This is the standard two point form taught in general chemistry; the Florida State University teaching pages derive it exactly this way and note that no knowledge of A is needed (chem.fsu.edu, course material). Temperatures must be absolute, in kelvin, or every term is wrong.

The gas constant and the exact CODATA value

Every joule per mole figure here leans on R. Since the 2019 SI revision, R is fixed by definition from the Boltzmann constant k = 1.380649 x 10^-23 J/K and the Avogadro constant N_A = 6.02214076 x 10^23 /mol, and the product is R = 8.31446261815324 J/(mol x K), exact with zero uncertainty. The CODATA recommended value listed by NIST reads 8.314 462 618... J mol^-1 K^-1, exact (NIST CODATA 2022 adjustment, physics.nist.gov). This calculator uses 8.314462618.

Two unit traps sit next to this constant. First, R must match the units of Ea: with R in J/(mol x K), Ea comes out in J/mol, and this page divides by 1000 to show kJ/mol. Second, the per molecule twin of R is the Boltzmann constant, k_B = R / N_A = 1.380649 x 10^-23 J/K, which equals 8.617333262 x 10^-5 eV/K. Reliability engineering models such as the NIST/SEMATECH e-Handbook Arrhenius acceleration model use that form, with the barrier written as Delta H in electronvolts and typical values of 0.3 to 1.5 eV (itl.nist.gov, NIST/SEMATECH e-Handbook, section 8.1.5.1). The calculator reports the eV per molecule equivalent so the two conventions line up.

ConstantValueUse
R, molar gas constant8.314462618 J/(mol x K)Ea in J/mol
k_B, Boltzmann constant1.380649 x 10^-23 J/KEa per molecule, J
k_B in eV/K8.617333262 x 10^-5Ea in eV per molecule
1 eV per molecule96.48533212 kJ/molunit conversion

Worked example 1: 64.2 kJ/mol from two rate constants

Put k1 = 2.0 x 10^-4 s^-1 at T1 = 300.0 K and k2 = 1.0 x 10^-3 s^-1 at T2 = 320.0 K. The ratio k2/k1 = 5, so ln(k2/k1) = 1.609438. The reciprocal difference is 1/300.0 - 1/320.0 = 0.00020833 1/K. Then:

Ea = 8.314462618 x 1.609438 / 0.00020833 = 64,232 J/mol = 64.23 kJ/mol

Enter the same two points in the calculator and it returns 64.23 kJ/mol, 0.666 eV per molecule, a pre-exponential factor of 3.05 x 10^7 s^-1, and a Q10 of 2.29 over the 300 to 310 K half of that span. The Q10 line answers the familiar rule of thumb directly: near room temperature a barrier of roughly 50 to 60 kJ/mol doubles the rate for every 10 K, which is where the rule comes from and why it is approximate.

Worked example 2: predicting a rate constant at a new temperature

The second mode runs the arrow the other way. Enter k1 = 1.5 x 10^-3 s^-1 at 25.0 degrees C, Ea = 75.0 kJ/mol, and a target of 35.0 degrees C. In kelvin that is 298.15 K to 308.15 K, so:

ln(k2 / k1) = (75000 / 8.314462618) x (1/298.15 - 1/308.15)

The bracket is 1.08829 x 10^-4 1/K and Ea / R = 9021.1 K, so ln(k2/k1) = 0.98175 and k2 = 1.5 x 10^-3 x 2.6695 = 4.00 x 10^-3 s^-1. The rate multiplies by 2.67 for a 10 K rise, a Q10 of 2.67, because the barrier of 75 kJ/mol is steeper than the 50 to 60 kJ/mol that generates the classic doubling rule.

Two readings of how big that is: stored food or a drug degrading with a 75 kJ/mol barrier loses that factor of 2.67 for each 10 degrees of storage warmth, and an Arrhenius plot of ln k against 1/T for the same data has slope -Ea / R = -9021 K.

Reading an Arrhenius plot

Take ln of both sides of k = A x exp(-Ea / (R x T)) and the equation becomes a straight line: ln k = ln A - Ea / (R x T). Plot ln k on the y axis against 1/T on the x axis and the points fall on a line with slope -Ea / R and intercept ln A. That plot is the usual way a lab reports activation energy, and the two point form above is just the line evaluated between two of its points.

What you measureWhat it means on the plotTypical size
Slope-Ea / R-6000 to -12,000 K for 50 to 100 kJ/mol
Interceptln A20 to 40 for first order reactions
CurvatureA or the mechanism changes with Tshould be none
Break in the linemechanism change or phase changetwo Ea values

A factor of 2 error in Ea shows up as a large error when you extrapolate. Extrapolating a fitted line more than about 20 to 30 K beyond the data is where Arrhenius predictions usually go wrong, so the calculator is most trustworthy inside the range your two measurements bracket.

Ea values for common reaction families

Barriers cluster by reaction type, and the table gives the ranges quoted in standard physical chemistry references. Values are apparent Ea for the overall reaction and can shift with solvent, catalyst, or mechanism.

ProcessTypical EaComment
Diffusion controlled in solutionunder 20 kJ/molnearly barrierless
Enzyme catalyzed20 to 50 kJ/molcatalyst lowered the barrier
Uncatalyzed solution reaction50 to 100 kJ/molthe doubling rule zone
Hydrogen abstraction by radicals30 to 60 kJ/molcombustion chemistry
Thermal decomposition of polymers150 to 300 kJ/molbonds must break
Diffusion in solid metals100 to 400 kJ/molatoms squeeze through a lattice

Where a barrier sits in that table tells you what a 10 K rise buys. A diffusion limited step at 15 kJ/mol speeds up by a factor of 1.22 for a 10 K rise near room temperature, while a 200 kJ/mol decomposition step speeds up by a factor of about 13.7 over the same span. That spread is why storage advice, cooking times, and shelf life estimates do not scale with one universal number.

Eyring, Q10, and the eV convention

Two neighboring frameworks get compared to Ea constantly. The Eyring transition state theory writes k = (k_B x T / h) x exp(-Delta G double dagger / (R x T)) and separates the barrier into enthalpy and entropy parts. For unimolecular solution reactions the link is close to Delta H double dagger = Ea - R x T, so at 298.15 K the enthalpy term runs about 2.48 kJ/mol below Ea, and the entropy term Delta S double dagger follows from ln(k x h / (k_B x T)). Transition state theory splits what Arrhenius lumps into A.

The Q10 temperature coefficient is just the ratio k2/k1 with T2 - T1 fixed at 10 K: Q10 = (k2/k1)^(10/(T2-T1)). Most biochemical processes run a Q10 near 2 to 3 at physiological temperature, and a Q10 of 1 marks a temperature independent process. The calculator computes Q10 from whatever interval you enter, so it works for 5 K or 20 K spans as well.

Finally, the electronvolt convention used in reliability engineering and solid state physics reports the barrier per molecule: Ea in eV equals Ea in kJ/mol divided by 96.485. A 64.23 kJ/mol barrier is 0.666 eV, and the NIST handbook acceleration factor between two temperatures uses the same exponential with k_B in eV/K.

Where the model stops

The Arrhenius equation is an empirical fit and it fails in identifiable ways. Below the glass transition or in enzyme systems past an optimum, rate falls with temperature instead of rising, and a Q10 below 1 is the signature of denaturation rather than of a smaller barrier. Barrierless reactions such as radical recombination can show a negative apparent Ea. Mechanism changes bend the Arrhenius plot, so a single two point estimate inherits whatever the mechanism was doing between the two temperatures. And the pre-exponential factor is not always temperature independent; when A varies as a power of T, a ln k versus 1/T plot curves slightly and a two point Ea picks up a bias.

Use the calculator as a interpolation and planning tool. Measure two rate constants at temperatures that bracket the range you care about, check that the Ea you get back is in a sensible range for the reaction family above, and only then extrapolate a few tens of kelvin. For kinetics work that needs enthalpy and entropy separately, run the Eyring analysis in the mode that reports Delta H double dagger and Delta S double dagger.

Frequently asked questions

What is activation energy in plain words?

It is the minimum energy a collision between reacting molecules must carry for the reaction to happen. Barriers of 50 to 100 kJ/mol are common for uncatalyzed solution reactions.

What formula does this calculator use?

The two point Arrhenius relation: Ea = R x ln(k2 / k1) / (1/T1 - 1/T2), with temperatures in kelvin and Ea in J/mol. The prediction mode rearranges it to solve for k2 given Ea.

What value of R does the calculator use?

8.314462618 J/(mol x K), the exact molar gas constant fixed by the 2019 SI and listed by NIST CODATA (2022). Temperatures are always converted to kelvin internally.

How do I convert Ea from kJ/mol to eV per molecule?

Divide by 96.485. A barrier of 64.23 kJ/mol is 0.666 eV, which is the convention used in reliability engineering Arrhenius models.

What is Q10 and what does a value of 2 mean?

Q10 is the factor by which a rate changes for a 10 K rise in temperature. A Q10 near 2 means the rate roughly doubles per 10 degrees, which corresponds to an Ea near 53 kJ/mol around room temperature.

Why must temperature be in kelvin?

The equation uses absolute temperature. A temperature of 25 degrees C entered directly gives nonsense; 298.15 K is the correct input. The calculator converts C for you.

Can activation energy be negative?

Apparent Ea can be negative for barrierless reactions such as some radical recombinations, where the rate falls slightly as temperature rises. The calculator still reports the value it computes.

How accurate is a two point Ea estimate?

It is exact if the data obey the Arrhenius equation perfectly. With experimental scatter, two points can carry the full measurement error, so labs fit many points and read Ea from the slope of ln k against 1/T.

What is a typical Ea for enzyme catalyzed reactions?

Roughly 20 to 50 kJ/mol after catalysis, lower than the 50 to 100 kJ/mol typical of the uncatalyzed reaction. Beyond an optimum temperature enzymes denature and the rate falls.

Does a catalyst change Ea?

Yes, it offers a lower barrier pathway, which raises the rate at the same temperature. It does not change the thermodynamics or the equilibrium position.

How much faster is a reaction at 35 C than 25 C with Ea of 75 kJ/mol?

A factor of 2.67, so a Q10 of 2.67. The same 10 degree span with a 50 kJ/mol barrier gives a factor of about 1.9.

What is the pre-exponential factor A?

It is the rate constant the reaction would have if the barrier were zero. For first order reactions A often lands between 10^12 and 10^16 s^-1, and the calculator backs it out from k1 and Ea.

How is Ea related to the enthalpy of activation?

For unimolecular reactions in solution, Delta H double dagger is approximately Ea - R x T, about 2.48 kJ/mol lower at 298.15 K. Eyring analysis reports the enthalpy and entropy terms separately.

Can I enter temperatures in degrees C?

Yes. Type the C value and leave the unit set to degrees C; the widget adds 273.15 and shows the kelvin values it used, so you can check the conversion.

Spotted a wrong number or a broken result?

More Converters tools

See all Converters tools

Fee schedules, rates and rules change without notice. Always confirm important figures with the official source before you rely on them.